Hello: My name is Betsy. I come to you no prior knowledge. So I am really looking for your guidance and expertise as I am flying by the seat of my pants.
I am interested in making this optical mouse camera scanner http://www.bidouille.org/hack/mousecam for an art project I am currently working on.
My question is: Is the Arduino code I am copying (and posted below) written to work with the ADNS-2051 optical sensor chip only? (I am using a ADNS-2610 optical sensor chip I am reading that it might be "interface compliant with the 2051 4--ADNS-2051/2610/2620 datasheet & application notes - Datasheet Archive) if the answer is yes it only works with the ADNS-2051 chip then my next question is: what aspects of the code do I have to modify to make this work for my chip?
Here is the Arduino code
#define SCLK 2
#define SDIO 3
#define PD 4
#define REG_PRODUCT_ID 0x00
#define REG_REVISION_ID 0x01
#define REG_MOTION 0x02
#define REG_DELTA_X 0x03
#define REG_DELTA_Y 0x04
#define REG_SQUAL 0x05
#define REG_AVERAGE_PIXEL 0x06
#define REG_MAXIMUM_PIXEL 0x07
#define REG_CONFIG_BITS 0x0A
#define REG_DATA_OUT_LOWER 0x0C
#define REG_DATA_OUT_UPPER 0x0D
#define REG_SHUTTER_LOWER 0x0E
#define REG_SHUTTER_UPPER 0x0F
#define REG_FRAME_PERIOD_LOWER 0x10
#define REG_FRAME_PERIOD_UPPER 0x11
int dumpWidth = 256; // Number of pixels to read for each frame.
byte frame[256];
void setup() {
Serial.begin(115200);
reset();
byte productId = readRegister(REG_PRODUCT_ID);
byte revisionId = readRegister(REG_REVISION_ID);
Serial.print("Found productId ");
Serial.print(productId, HEX);
Serial.print(", rev. ");
Serial.print(revisionId, HEX);
Serial.println(productId == 0x02 ? " OK." : " Unknown productID. Carry on.");
byte config = readRegister(REG_CONFIG_BITS);
config |= B00000001; // Don't sleep (LED always powered on).
writeRegister(REG_CONFIG_BITS, config);
}
void loop() {
// Allows to set the dump window by sending the number of lines to read via the serial port.
if(Serial.available() > 0) {
dumpWidth = 16 * Serial.read();
dumpWidth = constrain(dumpWidth, 0, 256);
}
readRegister(REG_MOTION); // Freezes DX and DY until they are read or MOTION is read again.
char dx = readRegister(REG_DELTA_X);
char dy = readRegister(REG_DELTA_Y);
Serial.print("DELTA:");
Serial.print(dx, DEC);
Serial.print(" ");
Serial.println(dy, DEC);
if( dumpWidth > 0 )
dumpFrame();
}
void dumpFrame() {
byte config = readRegister(REG_CONFIG_BITS);
config |= B00001000; // PixDump
writeRegister(REG_CONFIG_BITS, config);
int count = 0;
do {
byte data = readRegister(REG_DATA_OUT_LOWER);
if( (data & 0x80) == 0 ) { // Data is valid
frame[count++] = data;
}
}
while (count != dumpWidth);
config = readRegister(REG_CONFIG_BITS);
config &= B11110111;
writeRegister(REG_CONFIG_BITS, config);
Serial.print("FRAME:");
for(int i = 0; i < dumpWidth; i++) {
byte pix = frame[i];
if( pix < 0x10 )
Serial.print("0");
Serial.print(pix, HEX);
}
Serial.println();
}
void reset() {
pinMode(SCLK, OUTPUT);
pinMode(SDIO, INPUT);
pinMode(PD, OUTPUT);
digitalWrite(SCLK, LOW);
digitalWrite(PD, HIGH);
delayMicroseconds(1);
digitalWrite(PD, LOW);
}
byte readRegister(byte address) {
pinMode (SDIO, OUTPUT);
for (byte i=128; i >0 ; i >>= 1) {
digitalWrite (SCLK, LOW);
digitalWrite (SDIO, (address & i) != 0 ? HIGH : LOW);
digitalWrite (SCLK, HIGH);
}
pinMode (SDIO, INPUT);
delayMicroseconds(100); // tHOLD = 100us min.
byte res = 0;
for (byte i=128; i >0 ; i >>= 1) {
digitalWrite (SCLK, LOW);
digitalWrite (SCLK, HIGH);
if( digitalRead (SDIO) == HIGH )
res |= i;
}
return res;
}
void writeRegister(byte address, byte data) {
address |= 0x80; // MSB indicates write mode.
pinMode (SDIO, OUTPUT);
for (byte i = 128; i > 0 ; i >>= 1) {
digitalWrite (SCLK, LOW);
digitalWrite (SDIO, (address & i) != 0 ? HIGH : LOW);
digitalWrite (SCLK, HIGH);
}
for (byte i = 128; i > 0 ; i >>= 1) {
digitalWrite (SCLK, LOW);
digitalWrite (SDIO, (data & i) != 0 ? HIGH : LOW);
digitalWrite (SCLK, HIGH);
}
delayMicroseconds(100); // tSWW, tSWR = 100us min.
}
I am hoping that if these chips are interface compliant with each other that it means that I do not actually have to modify anything. However, I wanted to pose this question to you all.
Thank you for taking the time to read this and give me any help you might have.
betsy
