I have a simple project that utilizes ultrasonic sensor and LCD. It works great when powering the board (UNO) through USB but US sensor stops registering correct distance (and the the whole program freezes) when powering with 9v through VIN. I am using two new 9v in parallel and did multiple tests to confirm that that switching from USB to the internal power regulator (VIN) is what causes issues.
Any suggestions?
Your topic was MOVED to its current forum category which is more appropriate than the original as it has nothing to do with Installation and Troubleshooting of the IDE
I am guessing that they are type PP3 batteries and if so they simply cannot provide enough current at the required voltage as they are intended for use in low current applications such as smoke detectors
Have you measured the battery voltage whilst they are powering your project ?
Which Arduino board are you using ?
Put those batteries in smoke detectors and get a power supply or use several AA batteries in series. What you are stating your problem is extremely consistent with 9V batteries.
6xAA will work for a while. A 5V phone charger connected to Vcc (5V) will work too.
If all you have is 9V for a supply, use a step down converter (switchmode), to produce 5V and apply that to the 5V pin of the Uno. But not one of those 9V batteries, as mentioned.
Thank you. didn't realize - assumed, 9v batteries, being large in size, would provide plenty of current . Will try AA's. thanks.
Be inquisitive! Take one of your batteries apart. You will discover several tiny individual cells that are connected together in series to produce your 9+ volts. We call them batteries because the cells are in battery, meaning connected together, end to end.
I used to cannibalize 9V NiCad batteries to break out several tiny rechargeable 1.25V cells, because I couldn't find them that small anywhere else.
I did the same to get the connector off the top for use to connect a 9 volt battery to a new project. No need to buy ready-made connectors. Now I have a big bag of them left over form my old company. One customer used the plastic boxes that came with the wired connector, but did not use connector. Never throw away, because.
You are trading-off current for voltage... 
Power (Wattage) is calculated as Voltage X Current. A 1.5V battery of the same size and same chemistry could provide the same power/energy which means 6 times the current or 6 times the mA-hours.
Except actually, there is some wasted space with 6 cells in the rectangular battery so a 1.5V battery could hold a little more energy.
Pad soaked with lemon juice?
I prefer the burl oak housing.
Little smaller, - those that go into smoke-detectors. model name is 6LR61
Inside each of those batteries are 6 cells in series... providing 1.5v each.
Each cell is pretty small... hence the amount of current that can be provided is also small.
LOL!
I thought you were having us on after a bit of the old Photoshop applied to a picture of a PP3 9 volt battery.
But that PP9 size exists, can be purchased (saw prices from $13 to $20) and of course are solid time-tested carbon-zinc chemistry.
Which the old timers use for their vintage radios…
Now it makes more sense to use 6 AA batteries, rechargeable preferred.
a7
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