Reading pixel colour with Adafruit libary

hi, I am trying to get the colour of a pixel by its coordinates, I am not aware of a way to do this with the Adafruit_gfx library. I have a 1.44" tft screen that is using the Adafruit library and a Arduino pro mini, Any help is appreciated.

with the Adafruit_gfx library.

What a load of crap. Typing each function is not THAT hard.

That library does not provide a way of getting the color of a pixel.

The library makes extensive use of the drawPixel() function, but that function is virtual, and I can't see where it is actually implemented. There may be clues there that would let you read register values or something, to get the color that was set, if the device itself supports that. It may not. If I were writing the driver, I probably would not include a way to get the color of a pixel.

Typing each function is not THAT hard

What do you mean by this, I know there isn't a function for this otherwise I wouldn't be asking.

That library does not provide a way of getting the color of a pixel

So there could be another library I could use in conjunction with the Adafruit library to get the pixel colour?

What do you mean by this, I know there isn't a function for this otherwise I wouldn't be asking.

That POS library has:

 // These exist only with Adafruit_GFX (no subclass overrides)
void
drawCircle(int16_t x0, int16_t y0, int16_t r, uint16_t color),
drawCircleHelper(int16_t x0, int16_t y0, int16_t r, uint8_t cornername,
uint16_t color),
fillCircle(int16_t x0, int16_t y0, int16_t r, uint16_t color),
fillCircleHelper(int16_t x0, int16_t y0, int16_t r, uint8_t cornername,
int16_t delta, uint16_t color),
drawTriangle(int16_t x0, int16_t y0, int16_t x1, int16_t y1,
int16_t x2, int16_t y2, uint16_t color),
fillTriangle(int16_t x0, int16_t y0, int16_t x1, int16_t y1,
int16_t x2, int16_t y2, uint16_t color),

Now, really, how hard is it to type void a few times, and lose the stupid commas? And some white space? Is that too much to ask?

Looks like this crap was written to be deliberately obscure.