So it won't work with my 9v battery? I need a 12 battery?
Oh that's why it started burning. It couldn't work because it required 12v.
NO … as answered before in post 3 it started burning because you created a short circuit
IF you buy a 5V relay and connect everything as you show in post #19 with a 9V battery, it will work
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the symbols are a poor attempt to show where the switch would be.
Other module do a better job by making the lines longer
so the one on the right (the 2 wires seems to touch, being closed) is the normally closed and the other (which looks open) is normally open
In the future you really should get used to looking up and reading datasheets. Even if you don't understand everything on the sheet it will provide vital clues. Like a detective trying to piece together a mystery.
Just based on the photo you provided I simply looked up the datasheet and found it from the manufacture. This is the datasheet for just the relay since you did not communicate the manufacture of your relay board.
Start with the part number SLD-12VDC-SL-C
SLD = base part number
12VDC = 12 volt, direct current (This is the voltage rating for the relay coil)
S = Sealed
L = 36 watt coil power
C = Contact Arrangement
Statements retracted due to a total clueless statement of misunderstanding, although its quoted below for your entertainment.
Now powering your Arduino, the relay and the valve with the one battery might be a stretch depending on the capacity of the battery.
Regardless, you really need to do a little more research on your own before posting up looking for the quick answer. Learn to read the datasheet for every item your using in your project.
Advice I should have taken before making any of the above (or below) statements! 
Good Luck on your electronics journey, as well as my own.
I believe you are reading the data sheet incorrectly. The relay is available with several different coils, ranging from 5V to 48V. The coil data chart is showing, for each version of the relay, what the nominal coil voltage is, how much current the coil draws at that voltage, and the resistance of the coil itself at that voltage. You will not be able to reliably power a 12V coil with 9V, the resistance of the 12V coil is 400 ohms, at 9V the coil will draw 9V / 400ohm = 22.5mA, less than the normal 30mA at the rated 12V. The resistance from the chart is mainly useful if you want to use a high voltage, in which case the data is used to calculate the value of an external current limiting resistor.
40mA out of a 9v will last minutes!
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I am quite sure that is indeed true. I am still learning, just like the OP. I think I was just trying to illustrate that being able to read datasheets is an important skill to learn.
Just curious, can you elaborate on the different part numbers of this relay that would entail these many different variations in coils?
From the datasheet it looks like there are only 2 variations and both have the same range of voltages?
I am still learning, not trying to be difficult.
If you look at the data sheet, under ordering information, it describes the part number.
SLD is the part number for the relay itself
12VDC is the type of coil, this can be 5VDC/6VDC/9VDC/12VDC/18VDC/24VDC/36VDC/48VDC depending on which coil the relay contains.
S specifies sealed, this can also be F for dustproof
L is the coil power - L for 0.36W, D for 0.45W
C is the contact arrangement, the A and B types have only two contacts, A being normally open, B normally closed. C has three contacts, where the center contact switches between a normally open and a normally closed contact.
Sorry, I do not know how to post the actual image from the datasheet.
You ever have that moment where you feel really dumb?
How I can reference the datasheet, spell out the nomenclature of the part number and then turn around and be completely clueless makes me question my own intelligence.
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