[SOLVED]Need help with random LED sequence activated by a Push Button!

Projects General Guidance
1

I've encountered an annoying issue...
Basically, whenever the pushbutton is pressed the LED should display one of the 3 cases.
At the moment, it only displays case 0.

I need your help.

Here's my code, what's wrong with it?

int buttonPin = 2;   
int led =  13;    
int buttonState = 0;         

void setup() {
  pinMode(led, OUTPUT);      
  pinMode(buttonPin, INPUT);     
}

void loop(){


  buttonState = digitalRead(buttonPin);
  if (buttonState == HIGH) {
  switch (buttonPin == HIGH) {
  buttonState = random(3);

  case 0: 
  digitalWrite(led, HIGH);  
  delay(150);               
  digitalWrite(led, LOW);   
  delay(500);  //
 digitalWrite(led, HIGH);  
  delay(150);               
  digitalWrite(led, LOW);   
  break; 
  
  case 1:
    digitalWrite(led, HIGH);  
  delay(100);               
  digitalWrite(led, LOW);   
  delay(500);  //
 digitalWrite(led, HIGH);  
  delay(100);               
  digitalWrite(led, LOW);   
  break; 
  
   case 2:
    digitalWrite(led, HIGH);  
  delay(1000);               
  digitalWrite(led, LOW);   
  delay(100);  //
 digitalWrite(led, HIGH);  
  delay(1000);               
  digitalWrite(led, LOW);   
  break; 
  

 
  }  
  } 
  else {
    digitalWrite(led, LOW); 
  }
  }

Thanks!
Much appreciated!

2 
  switch (buttonPin == HIGH) {

So, you need cases for true and false.

  buttonState = random(3);

This does not belong in the switch statement. Only the cases belong.

   case 2:

buttonPin == HIGH will never evaluate to 2.

int buttonPin = 2;

Nor will it ever equal HIGH. Or LOW.

3

PaulS:

  switch (buttonPin == HIGH) {

So, you need cases for true and false.

  buttonState = random(3);

This does not belong in the switch statement. Only the cases belong.

   case 2:

buttonPin == HIGH will never evaluate to 2.

int buttonPin = 2;

Nor will it ever equal HIGH. Or LOW.

Thanks!
It works perfectly!