Using a HC4067 for 2 analogs read

hey, it s my 1st time using a multiplexer and i m having isues with understanding clearly how it works
I m working with an esp8266 who only has 1analog pin and i need to have 2analog reads so I chose an HC4067 (1to16 multiplexer) to be able to do both reads
Beacause I m using only 1 bit I only need to connect S0 to my board and have connected S1,s2,S3 to ground for it to stay 0
But my reads are really weird and constant I don t really understand
Here is thje portion of code I m curently working on but isnt working:

#define AOUT_PIN A0   // Broche commune du multiplexeur
#define SELECT_PIN D1 // Sélectionne le capteur (S0 du multiplexeur)
#define POWER_PIN  D7 // Alimentation du capteur de niveau d'eau

void setup() {
  pinMode(SELECT_PIN, OUTPUT);
  pinMode(POWER_PIN, OUTPUT);
  Serial.begin(115200);
}

void loop() {
  float soilMoisture, waterLevel;
  
  // read soil humidity(Canal 0)
  digitalWrite(SELECT_PIN, LOW);  // select C0
  delay(100);
  float anasm = analogRead(AOUT_PIN);
  soilMoisture = ((1024 - anasm) / 1024) * 100; //transform read in %
  
  // read water level (Canal 1)
  digitalWrite(SELECT_PIN, HIGH); // Sélectionne C1
  digitalWrite(POWER_PIN, HIGH);
  delay(100);
  waterLevel = analogRead(AOUT_PIN);
  digitalWrite(POWER_PIN, LOW);

  // Affichage des valeurs
  Serial.print("Soil Humidity : "); Serial.print(soilMoisture); Serial.println(" %");
  Serial.print("water level : "); Serial.println(waterLevel);

  delay(1000);
}

and the reads :
15:10:15.213 -> Soil Humidity : 99.02 %

15:10:15.213 -> water level : 1024.00

15:10:16.414 -> Soil Humidity : 99.02 %

15:10:16.414 -> water level : 1024.00

15:10:17.614 -> Soil Humidity : 99.02 %

15:10:17.614 -> water level : 1024.00

Are you powering the 4067 with 5V or 3.3V?
Does your ESP8266 board have a voltage divider on the analog input?
What is the voltage range you are trying to measure?

Does you code work correctly if you don't use the 4067?

Post an annotated schematic showing exactly how you have wired this. While doing this it will answer @jim-p questions and what I need to know.