The datasheet recommends a minimum V_in voltage of 6 V. However, from what I understand, there's a stepdown converter within that drops the current to 3.3 V. Why does it need to be 6 V minimum? I was planning on powering it with 5 V into the V_in; will this be fine, or do I really need above 6 V?
Doc: https://docs.arduino.cc/resources/datasheets/ABX00083-datasheet.pdf
I tried searching around existing posts but couldn't find a clear answer.
A very simple answer is that the regulator circuits need a higher voltage than the output in order to properly regulate and not be starved from working. That is called headroom.
That makes sense. Is there a test I can do to see if 5 V would be enough? Can I measure the voltage drop between the V_in and one of the GND pins and observe whether it's 3.3 V, for example?
I would have to say to do what the regulator data sheet advises because of many factors. The particular IC you have may work well with a given low voltage but, increased current output or higher operating temperature may require a higher input voltage. That kind of designing tends to bite us because it may work well today but be marginal another day.
You can hack a USB cable and run 5V through that.
Looking at the schematic, it appears that VIN is connected directly to the regulator whereas the USB-C/VUSB goes though a diode. So 5V should be sufficient?
5 posts were merged into an existing topic: Supplying Nano Esp32 with battery
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