While ago i created a project whic i dont want to work with that again. It is a remote for my other project. Im currently using it with usb wire. So i must plug it in to the phone charger or my pc. But i want to use li-po battery for that. So my question is whic voltage limits can arduino nano take from usb?
I dont want to use the V in pin (i dont want to take apart the hard case of my project, that wire is already out of the case)
Well, if it is a genuine Nano, then the path between the USB socket and the power to the Nano's processor chip is more or less direct. It just goes through a Schottky diode (0.4 volt loss).
Vin would anyway not be the correct pin to use because that goes through the voltage regulator. The +5V pin would be the right choice for a battery that did not exceed 5 volts.
Schematic: https://www.arduino.cc/en/uploads/Main/Arduino_Nano-Rev3.2-SCH.pdf
However, you may have to change the brown out voltage fuse settings if you are reducing the voltage.
You may have to reduce the clock rate to say 8MHz again by a fuse setting to avoid overclocking it.
Simplest would be to get cheap boost converter.
Hi,
If you use a 7.4V LiPo battery you can connect it directly to Vin pin. There will be some wasted power in the 5V voltage regulator, not the ideal condition for a battery powered circuit.
If you use a 4.2 V LiPo battery you should use a boost converter like 6v6gt already mentioned. Adafruit has a very cheap breakout: Adafruit MiniBoost 5V @ 1A - TPS61023 : ID 4654 : $3.95 : Adafruit Industries, Unique & fun DIY electronics and kits . If you use a 5V boost converter (in my opinion the best choice) you should connect the boost regulator output to the Arduino Nano 5V Pin.
A Nano is not suitable for battery power. It includes the USB-serial converter which will draw power even if the mega328 sleeps.
The most efficient way to power a Pro Mini is directly from the LiPo battery, but the 16 MHz version may not reliably run at 3.7 V. You want the 8 MHz version which is specified to run at 3.3 V but has no issues (the processor is after all, the same) at 5 V including for programming.
"Vin" is generally useless anyway and as the regulator may draw some standing current, you should disconnect it when running from a battery.
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