Exit error stray 302

So, I have code that does not work no matter what. No matter how many times I try, I can't get the 302 error out, but I wrote the entire thing. I tried removing the entire line, three lines and rewrite them, nothing worked: I still have the same 302 stray error on the same exact line. I need help, why is it that my own code has this issue? I do not know for what reason.
Someone suggested I have copied the code, but this is my first time writing code. Why would I copy bad code? My code can't be anything but bad as of now

#include <Servo.h>
Servo LOCK;
int Button1 = 2;
int Button2 = 3;
int Button3 = 4;
int ButtonPressed1 = 0;
int ButtonPressed2 = 0;
int ButtonPressed3 = 0;
int ButtonPressTime1 = 0;
int ButtonPressTime2 = 0;
int ButtonPressTime3 = 0;
char COMBO = ´´no´´;
char PASSWORD = ´´START, ONE, ONE, TWO, TWO´´;
int LOCKED = 1;

void setup() {
  LOCK.attach(5);
  pinMode(Button1, INPUT);
  pinMode(Button2, INPUT);
  pinMode(Button3, INPUT);

}

void loop() {
  ButtonPressed1 = digitalRead(Button1);
  ButtonPressed2 = digitalRead(Button2);
  ButtonPressed3 = digitalRead(Button3);
  while (ButtonPressed1 == HIGH) {
    ++ButtonPressTime1;
    delay(1);
  };
  if (ButtonPressed1 == LOW) {
    ButtonPressTime1 = 0;
  };
  while (ButtonPressed2 == HIGH) {
    ++ButtonPressTime2;
    delay(1);
  };
  if (ButtonPressed2 == LOW) {
    ButtonPressTime2 = 0;
  };
  while (ButtonPressed3 == HIGH) {
    ++ButtonPressTime3;
    delay(1);
  };
  if (ButtonPressed3 == LOW) {
    ButtonPressTime3 = 0;
  };
  if (ButtonPressTime1 >= 1000) {
    COMBO = COMBO + ´´, ONE´´;
    if (COMBO == PASSWORD) {
      LOCK.write(180);
      LOCKED = 0;
    } else {
      LOCK.write(0);
      LOCKED = 1;
    }
  };
  if (ButtonPressTime2 >= 2000) {
    COMBO = COMBO + ´´, TWO´´;    //this line has the issue
    if (COMBO == PASSWORD) {
      LOCK.write(180);
      LOCKED = 0;
    } else {
      LOCK.write(0);
      LOCKED = 1;
    }
  };
  if (ButtonPressTime3 >= 3000) {
    COMBO = 0;
    if (LOCKED = 0) {
      LOCK.write(180);
      LOCKED = 1;
    } else {
      LOCK.write(0);
    }
  }
}

Update: I have retyped everything in another IDE, then copied over. Same issue, different line. Now it's the same line but in the last block
COMBO = ´´START´´;

Where did you find these ?```

char COMBO = ‘ ‘no’ ´;
char PASSWORD = ´ ‘START, ONE, ONE, TWO, TWO’ ‘;

and elsewhere in the code..

‘ single quote
’ ‘ two single quotes
“ double quote

..and a c-string won’t fit into a single char, it needs to be an array[] of chars

wdym?

How do these char arrays work? I tried searching for it and did not get it. How do I do it and how do I then later recall it? Like after I say char COMBO i can then later just write "COMBO". What is the equivalent of this in the array? How do I add stuff to the array? I didn't get the stuff I found at all.
To explain: I am new to programming, this is my first time

Cross post to Three-button sliding lock code doesn't work

Kind of getting off on the wrong foot.
I don't want to sort your kit out.
Maybe you can learn from an example.

char coin1[] = "bitcoin,2,0.01234";
float holding;
float bonus = 100.1;   // just for fun

char scan;
byte idx = 0;
byte comma1;
byte comma2;

char field3[10];

byte f3;
byte LL;

void setup() 
{
  Serial.begin(19200);
  Serial.println("Go!");
}

void loop() 
{
  LL = strlen(coin1);
  idx = 0;
  
  findCommas ();
  //Serial.println(comma1);
  //Serial.println(comma2);
  
  idx = comma2 + 1;  // comma2 next place is field2=3
  f3 = 0;
  do
  {
    field3[f3] = coin1[idx];
    f3 ++;
    idx ++;
  }while (idx < LL);

  Serial.print("field3 = ");
  Serial.println(field3);
  holding = atof(field3);  // string to float
  holding = holding + bonus;
  Serial.println(holding, 5);
  
  delay(10000);
}

void findCommas ()
{
  do
  {
    scan = coin1[idx];
    idx ++;
  }while(scan != ',');
  comma1 = idx - 1;
  
  idx ++;
  
  do
  {
    scan = coin1[idx];
    idx ++;
  }while(scan != ',');
  comma2 = idx - 1;
}

Error has been fixed, but now program doesn't work. joy. now i will go and try to fix it with no knowledge in coding

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