xEnOnn:
Sembazuru:
There actually isn't a polyfuse on the nano (like there is on my UNO). There may be a polyfuse in the computer, but if the computer designers decided to allow more than 0.5A at the USB for charging purposes, the polyfuse might just be protection from shorting, not too much current draw. (Don't be worried about the name "polyfuse", they aren't like normal fuses that have to be replaced when tripped. Think of them more like automatic resetting circuit breakers. They will reset themselves when they cool down.)
Thanks for the really informative post!
Indeed, after the incident, my computer couldn't detect anything I plug into its USB port for the next few minutes before it started to work again. Is this the polyfuses at work?
Yes. That is what I would expect normal behavior from a circuit protected by a polyfuse.
If the current has to pass through the Schottky diode, you might be right that the Schottky diode is the one that was blown. It is quite close to the voltage regulator and I first thought it was the voltage regulator that was burnt. Still, even with magnifying glass, I can't see any burn marks on the chips.
I can sometimes be tough to see, particularly if the component burns out on the underside. I've repaired some boards where I thought a SMT component was blown and/or broken, but couldn't see any damage. It wasn't until I put the soldering iron on one end to start removing solder and then half the component came off with my solder wick.
So it looks like the bricking isn't caused by a short circuit too, but likely a sudden draw of more than 0.5A at the USB port? What are some possible scenarios that could cause a board to draw more than it suppose to? I only had simple components connected to the Nano, I can't quite understand how it would need so much more current that it burns itself. I'm worried that I may burn my next Nano board with the same circuit.
You also said previously regarding the dangling wires:
I suppose the 5v and ground when get in contact merely just completes a round trip circuit and shouldn't do any harm?
Actually, yes. Accidentally shorting the +5V line to ground while the circuit is being powered by USB could conceivably blow out the Schottky diode.
An interesting experiment would be to attach an external power supply (at least 7VDC, 5 AA batteries in series or a 9V battery would work) to the Vin pin. This will then power the circuit through the 5V regulator. If the problem is just the Schottky then your nano should work. Before trying that, check with an ohm-meter to make sure that the +5V pin isn't currently shorted to GND.
If the only problem is the blown Schottky, then you can continue to use this board with USB for data (programming, and Serial I/O) like normal, you would just need to have an external supply of at least 7V on the Vin pin.