I have a breadboard power supply module. Similar models on amazon show it has an output cap of 500 mA. What would happen if I put in a 4A DC power supply? I am trying to power multiple servos in this case so I would need more than 500 mA. How does the power module block current past 500 mA? and if I want to power multiple servos via breadboard with a 5v 4A DC power supply how can I do that? The module is convenient because it plugs directly into the +/- rails of the breadboard but idk what to make of the 500 mA cap.
Current is pulled, not pushed, so the 4A DC supply would be OK. The issue is if the motors pull more than 500mA, the module MAY cut off, drop voltage or be distroyed, without the datasheet for the module, I cannot tell you what would be the outcome.
So if I need to draw more than 500 mA (multiple servos) I would need a power module which could output enough current (more than 500 mA)? Is there another way to hookup the dc jack directly to the breadboard because I cant seem to find power modules which have a high enough max amperage.
Don't forget to account for I through a breadboard. Breadboards are limited with how much I they allow to flow; it's a tiny wire thing.
Running servos via a breadboard is a bad idea. The breadboard connections are not intended for high currents.
Steve
What does this mean ?
Is there another way to hookup the dc jack directly to the breadboard
Do you need a male or female dc plug with screw terminals ?
"https://www.amazon.com/gp/product/B07C61434H?pf_rd_r=VXYYSJQCQNPZH1Z3ZDZ3&pf_rd_p=edaba0ee-c2fe-4124-9f5d-b31d6b1bfbee"
Breadboard supplies are grossly over-rated.
Don't expect that you can pull 500mA from the 5volt pin if you power the supply with 9volt.
It's more like 300mA before the regulator overheats and hopefully reversibly shuts down.
With 12volt on the DC socket things get worse.
Leo..
A few points of confusion here.
The "DC Jack" - being what is commonly called the "barrel jack" with the 2.1/ 5 mm plug - feeds a 5 V regulator on the board. This means that depending on what sort of regulator is fitted, between the "barrel jack" and the breadboard pins when set to 5 V, you lose between 1,2 and 2 Volts at the very minimum. That is to say, if you provide 5 V in, you get 3 to 3.8 V out; you must supply at least 7 V to get 5 V out.
And the regulator has no real heatsink, so it will overheat and - hopefully reversibly - shut down if you draw more than a small current - a couple of hundred milliamps if fed from 9 V, less if fed from 12 as it is the voltage difference between input and output that is creating the heat.
If you want to feed 5 V into the module, you feed it into the USB connector (which takes different forms on different versions of the module). Most modules have a "polyfuse" rated at 500 mA between this connector and the 5 V line and when it cuts out at a greater current, it may take as much as a couple of hours to reset.