I don't think that's your problem . Ask yourself this, how would an aircraft pilot feel if he did not know how to navigate ? Now, assume that feeling because you do not know Ohm's Law.
So let'z see what Ohm's Law says about your comment.
I =15A (as we will see , this is only your power supply rating and has no relavancd per se to anything else because:
I = V/R
Let R= 4700 ohms.+ 100 Mohms
This is because the capacitor is NOT a load.
The RC LPF (resistor-capcitor low pass filter) connects the OUTPUT of the 1/30th voltage divider to the analog input which has an INPUT impedance in the order of 100 Mohms.
The ADC input current is 160 nA.
The volatge divider reduces the 30 V to 30*(1000/31000)= 0.967 V.
You refer to your regulator as a PWM regulator. If we assume you are saying the output is PWM, then the 0.967V is also PWM ( which of course means it would NOT read 0.967V on meter but would measure 0.967V peak to peak on a scope.)
The current through the 4.7 k ohm resistor is 160 nA.
Do you think that will blow anything up ?