Motor, limit switches and a rotary angle sensor

Projects General Guidance
42

It's hard to tell from the photo if there are any solder bridges. Using six wires of the same color makes it hard for you to connect correctly at the Arduino.

Based on post #37 the encoder output is not normal.

You purchased a used motor with no guarantee that the encoder would work.

My opinion from many miles away is that the encoder is broken.

1 Like
43

Did you read the link? Your encoder seems to have a quadrature output. Hard to rell exactly what your last image is.

Ron

1 Like
44

Hi,
Just of interesrt what is the application?
What speed do you aim to turn the output shaft at?

Have you been able to test the motor at that speed?

Thanks... Tom... :smiley: :+1: :coffee: :australia:

1 Like
45

Hi!
I'm making a robot finger.
I want to rotate the output shaft at 1000 rpm.
Tested the engine at this speed
But unfortunately I couldn't get the encoder to work

46

So you want the encoder to give you the position of the finger?
How many turns of the MOTOR shaft will that take?
I assume the encoder is connected to the motor shaft not the gearbox output?

Can you please post a basic diagram of the motor and finger mechanism?
Are you using a gear and rack, screw thread to move the finger?

Tom... :smiley: :+1: :coffee: :australia:

47

I use the so-called Worm Wheel mechanism.
Here is a photo:
image
image

In this connection, the encoder does not work, I can't say exactly how many revolutions I need, and if approximately, I need 5 revolutions.

the encoder is located at the bottom of the motor, unfortunately I do not know where it is connected.

I have a 3d model in development. But on the Internet there is an exact copy of the mechanism that I am doing now.

Here is the link:

48

Just FYI: a worm gear drive reduction ratio is quite simple:
for a single start worm, it is the number of teeth in the worm wheel.
So, if your wheel has 20 teeth, the reduction ratio is 20:1
In other words, a full rotation of the worm will advance the wheel by 1 tooth only.
If it is a two start worm, then the ratio is 2:20. As far as I can see from the picture, you have a single start worm.

Your motor will need to turn at 20 000 rpm if your worm gear reduction ratio is 20:1

1 Like
49

Hi,

How are you going to get the motor up to 1000rpm, turn 5 revs, then stop?

1000rpm = 1000 / 60 = 16.66 rps.

5 rev will take == 5 / 16.66 = 0.3s = 300ms.

And that assumes instant stop and start.

Thanks.. Tom... :smiley: :+1: :coffee: :australia:

1 Like
50

Thank you for the information!
I found 1000 prm motor encoder with difficulty. I'm unlikely to find 20,000 revolutions :grin: Because I need a very compact motor

51

Here I want to use limit switches for an exact stop.

52

The limits will disconnect the power from the motor, but what will stop the motor.
Inertia.

Its time to get some gear together and try to get the motor to start and stop in 5 revolutions.

Tom... :smiley: :+1: :coffee: :australia:

1 Like
53

Are there any other ways?
I thought I would turn off the power to the engine and it would stop by inertia :grin:

Could you please explain why we are doing this? :thinking:

I just want to check the encoder.
If it doesn't work, I want to fix it

If that doesn't help, I'll find another motor

54

It will overrun because of inertia.

I believe you have the wrong drive system, or at least the wrong motor characteristics.

Sorry, but you have bought a motor/encoder that has very little data available.

Tom... :smiley: :+1: :coffee: :australia:

1 Like
55

Could you please recommend the encoder motor?

The size and shapes should match the motor I have

56

I noticed that there is a black object in the back of the engine. When I turn on the motor, it rotates instead of the motor shaft.

Does that mean something?

57

That is a smoke container. Do not EVER let it get out!

58

This topic was automatically closed 180 days after the last reply. New replies are no longer allowed.