problem with 74hc595 shift register

Projects Programming
1

Hello I am trying to make a 16 led chasing leds with 2x 74hc595 shift register. The first shift register worked with 8 leds but when I tried extended it with another shift register and 16 leds, it is not working. Can anyone please help?

int latchPin=11;
int clockPin=9;
int dataPin=12;
int dt=200;
 
 int32_t LED1s=0b1000000000000000;
 int32_t LED2s=0b0100000000000000;
 int32_t LED3s=0b0010000000000000;
 int32_t LED4s=0b0001000000000000;
 int32_t LED5s=0b0000100000000000;
 int32_t LED6s=0b0000010000000000;
 int32_t LED7s=0b0000001000000000;
 int32_t LED8s=0b0000000100000000;
 int32_t LED9s=0b0000000010000000;
int32_t LED10s=0b0000000001000000;
int32_t LED11s=0b0000000000100000;
int32_t LED12s=0b0000000000010000;
int32_t LED13s=0b0000000000001000;
int32_t LED14s=0b0000000000000100;
int32_t LED15s=0b0000000000000010;
int32_t LED16s=0b0000000000000001;

 
void setup() {
  // put your setup code here, to run once:
Serial.begin(9600);
pinMode(latchPin,OUTPUT);
pinMode(dataPin,OUTPUT);
pinMode(clockPin,OUTPUT);
}
 
void loop() {
  // put your main code here, to run repeatedly:
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED1s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED2s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED3s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED4s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED5s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED6s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED7s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED8s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED9s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED10s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED11s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED12s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED13s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED14s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED15s);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,LED16s);
digitalWrite(latchPin,HIGH);
delay(dt);
}
2

shiftOut() can't send 16 bits, it only sends a byte (8 bits). It's in the first sentence of the Arduino documentation. If you put your bit patterns in an array, you won't have to repeat the same sequence of statements 16 times.

3

how do i do that?
Srry i am a not that experienced yet with arduino and shift registers

4

while i make a array do i put a decimal value of the binary number?

5

arrgh is this type of code that you were referring to be in an array

int latchPin=11;
int clockPin=9;
int dataPin=12;
int dt=200;

void store();
int one[] = {32768};
int two[] = {16384};
int three[] = {8192};
int four[] = {4096};
int five[] = {2048};
int six[] = {1024};
int seven[] = {512};
int eight[] = {256};
int nine[] = {128};
int ten[] = {64};
int eleven[] = {32};
int twelve[] = {16};
int thirteen[] = {8};
int fourteen[] = {4};
int fifteen[] = {2};
int sixteen[] = {1};

void setup() {
  Serial.begin(9600);
  pinMode(latchPin,OUTPUT);
  pinMode(dataPin,OUTPUT);
  pinMode(clockPin,OUTPUT);
}

void loop() {
    // put your main code here, to run repeatedly:
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,one);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,two);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,three);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,four);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,five);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,six);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,seven);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,eight);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,nine);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,ten);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,eleven);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,twelve);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,thirteen);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,fourteen);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,fifteen);
digitalWrite(latchPin,HIGH);
delay(dt);
digitalWrite(latchPin,LOW);
shiftOut(dataPin,clockPin,LSBFIRST,sixteen);
digitalWrite(latchPin,HIGH);
delay(dt);
}
6

i actually figured it out, I think i can use the bitset() function