Switch case question

Projects Programming
1

Why does the case in the below example keep giving offset = 0 ?
Regardless of the contents of #define IDENTIFIER 'C', if 'C' then ofset should be 10, yet a serial print shows 0.

#define IDENTIFIER 'C'
#include <Wire.h>
#include <Arduino.h>
#include <Adafruit_Sensor.h>
#include <Adafruit_BMP280.h>
#include "Adafruit_HTU21DF.h"
#include <ESP8266WiFi.h>
#define DS3231_I2C_ADDRESS 0x68
#define humidityLed 2  //built-in LED GPIO2: new message received
unsigned int disconnects, offset;

void setup() {
  Serial.begin(9600);
  delay(250);
  Serial.println(__FILE__);
  Wire.begin(4, 5);         // I2C 4 = SDA, 5 = SCL

  switch (IDENTIFIER) {
    case 'A':
      offset = 0;
      break;
    case 'B':
      offset = 5;
      break;
    case 'c':
      offset = 10;
      break;
    case 'D':
      offset = 15;
      break;
    case 'E': // reserve
      offset = 0;
      break;
  }
  Serial.print(F("offset = "));
  Serial.println(offset);
  Serial.println();
}

void loop()
{
}
2

My apologies!! I should have written capital 'C' inside the switch case code.

3

No

The option 10 is result for switch value 'c', that is not the same as 'C'.

4

If the offsets are spaced out evenly

offset = 5 * (IDENTIFIER - 'A');

with perhaps an additional check whether the result is out of bounds.

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