USB Power Backup (Battery)

Today, I purchased a new fancy school bag that included a Universal Charging Battery (Solar Powered) and I wanted to know if it would be powerful enough to run my Arduino Uno?

Specs: Li-ion 3.6V 1200mAh IN: DC 5V 400mAh OUT: DC 5V 450 mAh

5V at 450mA is plenty powerful. I'm guessing the spec is really 450mA and not 450mAh? The former is a measure of how much current it can supply, the latter a measure of energy storage capacity (of batteries e.g.)

Do you have a link to this backpack? It sounds like a really neat product.

-- The Aussie Shield: breakout all 28 pins to quick-connect terminals

RuggedCircuits: I'm guessing the spec is really 450mA and not 450mAh? Do you have a link to this backpack? It sounds like a really neat product.

The back does say mAh. Here is a picture of the unit:

Well, then I'm confused. The battery is 3.6V 1200mAh...I don't know where the other mAh numbers are coming from.

-- The Rugged Motor Driver: two H-bridges, more power than an L298, fully protected

Is it possible since the Battery is designed for recharging Mobile devices it's output is only 5V/450mAh instead of 1200?

It is too powerfull for simple runing arduino dependig what yo wish arduino to do and how long time

rabits: It is too powerfull for simple runing arduino dependig what yo wish arduino to do and how long time

Are you saying it will fry the Arduino if plugged in?

woah there, if its a regulated 5 volt output then nothing will be in danger of being fried. and i think the conversion in mAh comes from the boost converter. to get 5 volts from 3.whatever you need to drop the current capacity, so more amp draw on the battery in exchange for more voltage. so long as the energy is the same (minus conversion losses) it works out.

[edit: the input of 400mAh makes no sense however]

weirdo557: woah there, if its a regulated 5 volt output then nothing will be in danger of being fried. and i think the conversion in mAh comes from the boost converter. to get 5 volts from 3.whatever you need to drop the current capacity, so more amp draw on the battery in exchange for more voltage. so long as the energy is the same (minus conversion losses) it works out.

[edit: the input of 400mAh makes no sense however]

Thanks. I think the Input might have to do with it being Charged by USB or by the Solar Panel.