Weather station with esp32 and ePaper waveshare

Projects General Guidance
1

Hello everyone,

I'm a bit new to the programming world and wanted to try my hand at a finished product.
I came across the following project:

Now I have wired everything up and checked it 3 times, but the display still shows nothing. So I started debugging and came across the following message:

rst:0x1 (POWERON_RESET),boot:0x13 (SPI_FAST_FLASH_BOOT)
configsip: 0, SPIWP:0xee
clk_drv:0x00,q_drv:0x00,d_drv:0x00,cs0_drv:0x00,hd_drv:0x00,wp_drv:0x00
mode:DIO, clock div:2
load:0x3fff0030,len:1184
load:0x40078000,len:13232
load:0x40080400,len:3028
entry 0x400805e4
Battery voltage: 4212mv
Connecting to 'MeinWLan'...
Waiting for SNTP synchronization........
Friday, March 21, 2025 16:41:19
Attempting HTTP request: ...
200 OK
Attempting HTTP request: ...
200 OK
Reading from BME280... Success
Busy Timeout!
_PowerOn : 20001251
Busy Timeout!
_Update_Full : 20001231
Busy Timeout!
_PowerOff : 20000107
Busy Timeout!
_PowerOff : 20000107
Awake for 87.235s
Entering deep sleep for 1039s

epaper: 7.5" 800×480 ePaper Display HAT für Raspberry Pi, dreifarbig (rot, schwarz, weiß... - kaufen bei BerryBase
Borad: DFRobot FireBeetle ESP32-E IoT Microcontroller (WLAN & Bluetooth) - kaufen bei BerryBase

I bought and connected the components as described in the project.
I really don't understand the error any more. Can anyone help me?

2

What error are you referring to? Looks like messages from the program as it runs. You can find all the messages and reason for them in the program code.

3

you can do more with a BME 280 than you may think:

void BME_280_conversions()
{
  temperature_C = (temperature.toInt());
  Serial.print("Temperature C = ");
  Serial.print(temperature_C);
  Serial.println(" *C");
  temperature_F = ((1.8 * temperature_C) + 32); // Convert Celcius temperature to Fahrenheit
  Serial.print("Temperature F = ");
  Serial.print(temperature_F);
  Serial.println( " F" );

  Pressure = (pressure.toInt());
  pressure_hPa = ((Pressure / 100.0F));
  Serial.print("Pressure hPa  = ");
  Serial.print(pressure_hPa);
  Serial.println("  hPa" );
  pressure_inHg = ((pressure_hPa / 100.0F) / 33.864); // Convert hectoPascals to inHg
  Serial.print("Pressure inHG = ");
  Serial.print(pressure_inHg);
  Serial.println( " inHG");

  Humidity = (humidity.toInt());
  Serial.print( "Humidity      = ");
  Serial.print(Humidity);
  Serial.println(" %");

  seaLevelPressure_hPa = pressure_hPa / pow(1.0 - 0.0065 * localElevation / (temperature_C + 273.15), 5.255);
  Serial.print( "Sea Level Pressure hPa  = " );
  Serial.print( seaLevelPressure_hPa );
  Serial.println( " hPa");
  seaLevelPressure_inHg = seaLevelPressure_hPa / 33.864;
  Serial.print( "Sea Level Pressure inHg = " );
  Serial.print( seaLevelPressure_inHg );
  Serial.println( " inHg");

  dewpoint_F = 243.04 * (log(Humidity / 100) + ((17.625 * temperature_F) / (243.04 + temperature_F))) / (17.625 - log(Humidity / 100) - ((17.625 * temperature_F) / (243.04 + temperature_F)));
  Serial.print("Dewpoint = ");
  Serial.print(dewpoint_F);
  Serial.println(" F");
  dewpoint_C = ((temperature_F - 32) / 1.8 ); // Convert Fahrenheit temperature to Celcius
  Serial.print("Dewpoint = ");
  Serial.print(dewpoint_C);
  Serial.println(" C");
  Serial.println();
}```

the variables:

float temperature_C; // Initialize variables to get and save Weather data
float temperature_F;
float pressure_hPa;
float Pressure;
float pressure_inHg;
float Humidity;
float seaLevelPressure_hPa;
float seaLevelPressure_inHg;
float dewpoint_F;
float dewpoint_C;

4

Unfortunately, I have no display on the ePaper and I have identified this busy timeout as the error description. I can't explain anything else

5

Ok, but that shouldn't be my problem. I want to see something on the display first and then I want to add these points if necessary.

6

For a well written program that only means there is a timeout on some operation and that operation is being retried until successful.