BC = {(Iout*3600/ 2000)*100%};
Because it's not valid C/C++?
Where are you entering this?
In loop
You mean inside the loop() function in your arduino sketch. Ok. In your Arduino sketch, you must use only valid C/C++.
Braces {} are not used in formulae in C/C++.
% is the modulo operator and requires a number to the left and another number to the right.
If by % you meant percentage, you cannot use % like that in C/C++. Simply convert it to a fraction. In this case, since the value is 100% == 1.00, you can remove it because it has no effect on the result.
To summarise: you need to learn to code in C/C++.
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Hi, @natanajithg
Can tell us in words how you want your equation to work?
What are the { and } for?
What is the 100% for?
What is the application?
Thanks.. Tom.. 
Get rid of the curly brackets { }.
You also can't use % in the expression. Probably remove that too.
Since the math is fixed can it not be done outside the code
3600 / 2000 = 1.8
1.8 * 100% = 1.8
all in all
float BC;
BC = lout * 1.8;
If your real formula uses more variables you have to post the real formula with all variables
best regards Stefan
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