breaking out the rx tx indicators

after following the instructions to burn a bootloader successfully at

http://www.instructables.com/id/Atmega-Standalone-Running-without-crystal-oscillat/?ALLSTEPS

i got to thinking i may consider developing a bootloader burning shield.

i looked at the schematic of the arduino uno r3 at

i found that the rx and tx indicators are directly connected to pins 10 and 11 of the atmega chip

unfortunately when i using my multimeter to verify that it turns out that the leds are not connected to the pins 10 and 11.

the reason i want to break out the pins is because most shields would cover the indicators witch is critical for verifying board response.

it is possible that i could drill holes into a blank shield board and install light pipes or some short piece of fiber optic string to bring the indicators to the top.

i would like to build a bootloader burner shield to make it easier to install boot loaders without all the complex wiring of a breadboard and then the possibility of corrupting or even burning out the chip or something bad.

thanks for the help

Look at the schematic once more. The LED's are connected to the Atmega16U2 (USB-converter) - and not the main 'Arduino'-IC.

You could extend the lights with light pipes or monitor the actual serial lines on Arduino pin 0 & 1 - You can do this with some transistors, resistors and LED's

// Per.