How to connect JST pin to arduino on perfboard

Hi,

Super-basic question.
What's the best, easiest way (that follows best practices) to connect an Arduino pin to the perfboard?
This is what I have:

Do I join the pin with the hole next to it on the board? Do I solder straight on the arduino pin? (But, they are really close... feels dangerous, in case the wire sticks out a little etc.)

How is it done normally?

Merc.

Personally I would put the Nano in a socket in case I needed to change it later

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I will do that!

Personally I use the boards having long continued copper stripes. For all DIL circuits I just cut the stripes under the circuit. That way building mountain ridges, baking, with tinn is avoided.

I am sorry, I can't say I understood what you meant.

Merc.

Most of the time, connectors go at the edge of the board (as your first image shows). In your case, you will use wires to to connect the connector to the Nano pins.

If you use strip board (as mentioned by @Railroader), you can cut the cut the strips at specific places; I usually use a drill bit that I roll between my fingers.

image

The image below is taken from https://www.nutsvolts.com/magazine/article/june2013_Dratwa

If you look closely at the the two rows of the zif-socket (in the centre), you will see that they were cut so the one row of pins does not connect to the other row of pins; there are probably other "breaks" in the strips but they are not as clear (e.g. for the dip switches.

This is what my board layout is:

But consider that wack JST connector will need ground and power. So each one will need a break (or it will go straight on some random Arduino pin).

This is the back of my Arduino;

Is it easy to make these breaks, and are they reliably separated?

Look up veroboard, or strip board.

They do make special tools, or you can use a pin-vice with 5mm drill bit, or a Dremel,using a round burr.

It's easy to make them; you have been given some advice regarding that. You only have to break the copper.

You use a multimeter to make sure that all breaks are indeed breaks.

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