my code says exit status 1 when i try to upload it
Which board?
Which operating system?
Correct port selected?
Just making sure: do you get the error during the verify phase or during the actual upload phase of an upload?
adruino uno r3
???
Yes
You did not answer the above question
Don't you know if you're using Windows or Linux or Mac or ... ?
OK, assuming that this is indeed an upload error, please enable verbose output during upload and disable verbose output during compilation in file/preferences in the IDE. Perform an upload and post the complete output here using code tags (see https://forum.arduino.cc/t/how-to-get-the-best-out-of-this-forum/679966#use-code-tags).
PS
I did forget to ask: which version of the IDE you are using?
I'm usiing mac ans version 2.3.3 and it is an upload error
/var/folders/70/52w6t8_s4977b49cvlsynlk40000gn/T//cculbpfp.ltrans0.ltrans.o: In function setup': /Users/radley/Documents/Arduino/sketch_oct07a/sketch_oct07a.ino:9: undefined reference to loop'
/var/folders/70/52w6t8_s4977b49cvlsynlk40000gn/T//cculbpfp.ltrans0.ltrans.o: In function main': /Users/radley/Library/Arduino15/packages/arduino/hardware/avr/1.8.6/cores/arduino/main.cpp:46: undefined reference to loop'
collect2: error: ld returned 1 exit status
exit status 1
Compilation error: exit status 1
This is the error message
And that would be?
void setup() {
// put your setup code here, to run once:
int sensorPin = 0;
void setup ();
Serial.begin(9600);
void setup();
loop();{
}
int reading = analogRead(sensorPin);
float voltage = reading * 5.0;
voltage /= 1024.0
;Serial.println(voltage); Serial.println ("volts");
delay(1000);
}
See this tutorial for the structure of an Arduino sketch, and how to use setup( ) and loop ( ).
https://arduinogetstarted.com/tutorials/arduino-code-structure
Also pay attention to your use of the curly braces { and } .
https://www.arduino.cc/reference/en/language/structure/further-syntax/curlybraces/
1 Like
ok thank you
And semicolons…
loop();{
that one just don't belong there at all.
a7
1 Like
/Users/radley/Documents/Arduino/sketch_oct07a/sketch_oct07a.ino:10:1: error: expected unqualified-id before '{' token
{loop();
^
exit status 1
Compilation error: expected unqualified-id before '{' token
what does this mean?
void setup() {
// put your setup code here, to run once:
int sensorPin = 0;
void setup ();
Serial.begin(9600);
}
void setup();
int reading = analogRead(sensorPin);
float voltage = reading * 5.0;
voltage /= 1024.0
;Serial.println(voltage); Serial.println ("volts");
delay(1000);
}
is that better?
You should look at a few example sketches to try and catch the syntax. Or read or watch some learning materials.
Please use the <CODE/> button in the message composition window to post your code.
Apply the IDE Autoformat tool to your code fist. It should end up looking like this
void setup() {
// put your setup code here, to run once:
int sensorPin = 0;
void setup ();
Serial.begin(9600);
}
void setup();
int reading = analogRead(sensorPin);
float voltage = reading * 5.0;
voltage /= 1024.0
; Serial.println(voltage); Serial.println ("volts");
delay(1000);
}
You have two attempts at defining the setup() function, the first is correct and only one is allowed. And a spurious reference to setup() within the setup() function itlsef.
It looks like you were trying to define the loop() function but called it setup(). And the semicolon is out of place there, and you have unbalanced { braces }.
Semicolons come at the end of statements, so your formatting is wrong in a way Autoformatting can't (or does not) fix.
Here's what you prolly meant, please study it to see how it differs. Syntax is a bitch until it isn't. 
I also moved a variable declaration out of setup(). This is a matter of variable scope, which should be on your short list to get your head around. Google is your friend, add "C++" and "Arduino" to any searches to focus things a bit.
int sensorPin = A0; // 0 works, but A0 is the more common way to refer to analog input zero.
void setup() {
Serial.begin(9600);
}
void loop() // not setup! thx and a tip o' the hat to @outbackhut
{
int reading = analogRead(sensorPin);
float voltage = reading * 5.0;
voltage /= 1024.0;
Serial.print(voltage);
Serial.println (" volts");
delay(100); // 1000? Life is too short, let's speed thing up a bit here 'K?
}
HTH
a7
It's not an upload error, it's a compilation error; see below.
The upload process consists of two steps.
- Compile the code.
- Upload the code.
In your case, the first step fails.
1 Like
int sensorPin = A0; // 0 works, but A0 is the more common way to refer to analog input zero.
void setup() {
Serial.begin(9600);
}
void loop() {
int reading = analogRead(sensorPin);
float voltage = reading * 5.0;
voltage /= 1024.0;
Serial.print(voltage);
Serial.println (" volts");
delay(100); // 1000? Life is too short, let's speed thing up a bit here 'K?
}
Is not having two setups going to stuff things up? I'm assuming you meant loop...
I know I'm a little loopy, and it probably makes no difference, but I don't like overwriting a variable halfway through the arithmatic...
void loop() {
int reading = analogRead(sensorPin);
float voltage = reading * 5.0;
float volts = voltage / 1024.0;
Serial.print(volts);
Serial.println (" volts");
delay(100); // 1000? Life is too short, let's speed thing up a bit here 'K?
}
1 Like
Change to this
float voltage = (reading * 5.0)/1024.0;
Serial.print(voltage);
2 Likes
Your original code had 3 x Setup() and no Loop()
There must always be just 1 setup and 1 Loop.
I assume you mean the OP's original code. I'm not the OP, I was questioning @alto777 for including two setups and no loop.
My point exactly.
That's neater.
Sorry you are correct I notice that but don't know how to fix it.