Oh boy, don't get me started. I got mine for $95 at HSC
Now I may be incorrect but I think the circuit has to be isolated as it reads resistance and I don't think I should introduce any extra current or voltage to it.
At the risk of being actually helpful, I would point out that the current is a function of the voltage and resistance, as expressed by Ohm' Law (V = I*R => I = V/R)
I would say that to be more accurate, the chip is reading the difference between the voltage drop when the button is not pressed (V= I*R) and the voltage drop when the button is pressed (V = 0, by because the contacts of the switch are at the same potential when pressed)
I would submit that if you , for reason we can't imagine, were to decide you wanted to actually KNOW what effect resistance has on your circuit board, you could easily do that by inserting a potentiometer (a low value such as 300 ohms, or at most 500 ohms) IN SERIES with the relay contacts you currently have and recording the resistance across the series pot (wired as a 2-pin rheostat) , starting at 0 ohms ,(measured with the power off) and increasing in resistance at 20 ohm increments, each time turning off the power to record the value, then turning on the power to test the board using the normal system test procedure. Collect the data, put it in an Excel file , save it as "
"Allowed file types: doc, gif, jpg, mpg, pdf, png, txt, zip, c, h, cpp, ino, pde
Restrictions: maximum total size 1 MB, maximum individual size 1 MB"
and post it as a table, that shows the increasing resistance values and on the same line the operational status of the circuit board when operated with that specific amount of resistance inserted;
ie:
R Status
0 OK
20 OK
40 OK
60 OK
80 OK
100 OK
120 FAILED
This test should yield similar results regardless of which switch you insert the series resistance in since the electrical properties of the chip are the same for all the switches.
By performing this experiment, you could INCLUDE/EXCLUDE relay alternatives that have been recommended in this post. It is only necessary to have one pot , since the data collected is going to be the same for any of the switches, it makes no difference which switch you choose to use for the test.
P.S.- Don't tell anyone I told you this. I wouldn't want to ruin my reputation of not being helpful...